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2x^2-70x+612=0
a = 2; b = -70; c = +612;
Δ = b2-4ac
Δ = -702-4·2·612
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-2}{2*2}=\frac{68}{4} =17 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+2}{2*2}=\frac{72}{4} =18 $
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